Can you find the values of X, Y, and Z?

Hii friends this is Pritam here.

Here is a fun problem. We have two numbers one is XYZ and the other is ZYX. And we add these two numbers and get ZX0.

So here is the question, that what is the value of X, Y, and Z, such as that X, Y, Z>0?

…………………….. Solution………………………..

1st we look to this part. We can see that sum of Z and Y is 0, it means it should be 10, it should not be 20, 30 or any number which ends with 0 because the max value of Z and Y should 9, therefore, Z+Y will be 18
And min value of Z and Y should be 1 therefore the sum will be 2, So here is only one possible number 10 which has 0 as the last digit.

Therefore Z+Y=10.
And we sift the carry here.

So, 1+Y+Z=X, but as we know the value of Z+Y, so we just put the value here.
And we get X=11, therefore we take the rightmost digit as the value of X.
so x=1.

And again we sift the carry to here, therefore 1+X+Y= Z, as we already know the value of X therefore we put the value of X here. So we get Z-Y=2.

till now we have got 3 equations, so by solving the 1st and 3rd equation we can easily find the value of Z and Y, so we get Z=6 and Y=4.

Therefore we get, X=1, Y=4, and Z=6.

So the two numbers are 146 and 464 and their sum is 610.

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